A heavy chain with mass per unit length ‘ ρ ’ is pulled by the constant force F along a horizontal surface consisting of a smooth section and a rough section. The chain is initially at rest on the rough surface with x = 0. If the coefficient of kinetic friction between the chain and the rough surface is µ k , then what is the velocity v (in m/s) of the chain when x = L, if the force F is greater than µ k ρ gL in order to initiate the motion.: If F = 21N, μ = 0.5, L = 1 m, ρ = 2 kg/m
Text Solution
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(4)
Sol. Considering the forces on the chain for the given situation we have
F – μ k ( λ – x) ρ g = λ ρ a
– 
= 
.v.
– 
= 
– 
– 
= 
= v = 4 m/s
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